Posted by **Physics Guy** on Sunday, November 2, 2008 at 10:23pm.

A 5 kg mass is thrown down with a velocity of 10 m/s from a height of 20 m onto an upright spring with a relaxed length of 10 m, and a constant of 50 N/m. What will the maximum compression of the spring be? What will the speed of the object be when the spring is compressed 0.2 m?

Here's what I have so far:

INITIAL HEIGHT = 20 meters

FINAL HEIGHT = 10 meters

MASS = 5 kilograms

ACCELERATION = 9.8 meters per second squared

INITIAL VELOCITY = 10 meters per second

SPRING CONSTANT = 50 Newtons per meter

ENERGY OF GRAVITY = mgh

KINETIC ENERGY = 0.5mv^2

SPRING ENERGY = 0.5kx^2

TOTAL ENERGY = The sum of those 3 energies

I need to find the final velocity and then how much the spring gets compressed. Then I have to find the speed of the object when the compression of the spring is 0.2 meters.

- ! P H Y S I C S ! -
**drwls**, Sunday, November 2, 2008 at 11:17pm
The spring in compressed until the initial sum of kinetic and potential energy equals the final stored energy in the spring, MINUS the decrease in PE during compression.

Let x be the maximum compression

(1/2) M Vo^2 + M g H = (1/2) kx^2 - M g x

Solve for maximum x deflection. When the spring is compressed x = 0.2 m, you can energy conservation to solve for v

(1/2) M Vo^2 + M g H = (1/2) kx^2 - M g x + (1/2) M v^2

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