Post a New Question


posted by on .

the curve: (x)(y^2)-(x^3)(y)=6


a) find all points on the curve whose x-coordinate is 1 and write an equation for the tangent line of each of these points

b)find the x-coordinate of each point on the curve where the tangent line is vertical

  • Calculus - ,

    a) If x = 1, y^2 -y -6 = 0
    (y-3)(y+2) - 0
    y = 3 or -2

    b) Find the points where dy/dx = infinity

    Those would be the places where the denominator of dy/dx = 0. x=0 is one such point. Any point where x^2 = 2y would be another, if there is such a point on the curve.

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question