Posted by Anonymous on Sunday, November 2, 2008 at 12:13pm.
If you can't reason through to the answer, why not just work the problem and see what the pH is for the two solutions.
For example, for the HCN:
CN^- + HOH ==> HCN + OH^-
Kb = Kw/Ka = (HCN)(OH^-)/(CN^-)
Plug in the values for Kw, Ka, and (CN^-) and solve for (OH^-). (Remember HCN = Y and OH = Y so the numerator is just Y^2.
Do the same for KNO2.
Y^2/0.1 = 1 x 10^-14/4.9 x 10^-10. You need to look up the value for Ka for HCN and HNO2. I'm using an OLD set of tables.
lol, mcmaster first year chem quiz...i bet you anything that he/she is in life/health science...
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