Posted by Kiley on Sunday, November 2, 2008 at 12:03pm.
The sixth force is the opposite (negative) of the sum of the first five vectors. Add them up.
You obviously need some practice in vector addition.
yeah, i do.
I don't understand how to do it or i would practice.
I assume you are measuring angle from the +x axis (not North)
Add up the five X components
60 * cos 90 = 0
40 * cos 0 = 40
80 * cos 270 = 0
40 * cos 180 = -40
50 * cos 60 = 25
sum = 25 N in x direction so the sixth has -25 N in x direction
Then y components
60 * sin 90 = 60
40 * sin 0 = 0
80 * sin 270 = -80
40 * sin 180 = 0
50 * sin 60 = 43.3
sum = 23.3 so force six has y component = -23.3
magnitude of F6 = sqrt (25^2 + 23.3^2)
negative x and negative y means quadrant 3
tan theta = -23.3/25
theta = 43 degrees below -x so
180+43 = 223 degrees
tan theta = -23.3/-25
25 * ( sin 40 )
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