Posted by **austin** on Saturday, November 1, 2008 at 11:43pm.

this is real hard and i would love some help.

In a game of craps, a player rolls 2 balanced dice. There are 36 equally likely outcomes. What is the probability that:

a) the sum is either 3 or 8

b) the sum is 6 or doubles rolled

c) the sum is 6 AND doubles

d) the sum is 6 and both numbers are odd

please help

- math -
**PsyDAG**, Sunday, November 2, 2008 at 1:38am
If there are 36 possible outcomes, you are always dividing by 36.

For A, you can get 4 possibilities:

2,1

1,2

6,2

2,6

There are no other ways the dice will total 3 or 8.

The other problems can be solved by similar logic.

I hope this helps. Thanks for asking.

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