write the total and net ionic equation for
calcium hydroxide(aq) -> acetic acid(aq)
Surely you didn't intend to type an arrow. I assume you meant for these two compounds to react. (To help shorten this process let's call acetic acid HAc). The molecular equation follows:
Ca(OH)2(aq) + 2HAc*(aq) ==> Ca(Ac)2(aq) + 2H2O(l)
To each of the ions I write below, add (aq) to each except for the H2O. That will save me some typing. The ionic equation follows:
Ca^+2 + 2OH^- + 2HAc ==>Ca^+2 + 2Ac^- +
2H2O(l)
Net ionic equation follows:
2OH^-(aq) + 2HAc(aq) ==> 2Ac^-(aq) + 2H2O(l)
To write the total and net ionic equation for the reaction between calcium hydroxide (Ca(OH)2) and acetic acid (CH3COOH), we need to keep in mind some basic rules.
First, we should recognize that calcium hydroxide is a strong base and acetic acid is a weak acid. Strong bases dissociate completely in water, while weak acids partially dissociate.
The chemical equation for the reaction can be written as follows:
Ca(OH)2(aq) + 2 CH3COOH(aq) -> Ca(CH3COO)2(aq) + 2 H2O(l)
This equation represents the reaction where calcium hydroxide reacts with acetic acid to form calcium acetate and water.
Now, let's break this equation down into the total ionic equation. In the total ionic equation, all the strong electrolytes (which are soluble ionic compounds) are represented as ions:
Ca^2+(aq) + 2 OH^-(aq) + 2 CH3COOH(aq) -> Ca^2+(aq) + 2 CH3COO^-(aq) + 2 H2O(l)
In the total ionic equation, you can see that Ca^2+ ions and CH3COO^- ions appear on both sides of the equation. These ions are called spectator ions because they are present on both sides and do not participate in the actual chemical reaction.
To obtain the net ionic equation, we need to cancel out the spectator ions. In this case, the calcium ions (Ca^2+) and acetate ions (CH3COO^-) are spectator ions, so we can remove them from the equation:
2 OH^-(aq) + 2 H^+(aq) -> 2 H2O(l)
Finally, this net ionic equation shows that hydroxide ions (OH^-) from calcium hydroxide react with hydrogen ions (H^+) from acetic acid to form water.
Therefore, the total ionic equation is Ca^2+(aq) + 2 OH^-(aq) + 2 CH3COOH(aq) -> Ca^2+(aq) + 2 CH3COO^-(aq) + 2 H2O(l), and the net ionic equation is 2 OH^-(aq) + 2 H^+(aq) -> 2 H2O(l).