Posted by **Carmen** on Saturday, November 1, 2008 at 7:09pm.

Q1) there are two plans available, but they only have 38 homes available. write an equation that illustrates the situation. use x and y to denote plan 1 and plan 2.

A1) X+Y=38

Q2)Plan 1 sells for $175,000 and plan 2 sells for $200,000. All available houses combined are worth $7,200,000.

What is the equation using same variable from (a).

A2) 175,000X+200,000Y=7,200,000

Q3)Use elimination to determine how many houses in each floor plan available. Explain how you got the answer.

A3) X=38-Y, so you can substitute that into the second equation:

175,000(38-Y)+200,000Y=7,200,000

6,650,000-175,000Y+200,000Y=7,200,000

6,650,000+25,000Y=7,200,000

25,000Y=7,200,000-6,650,000

25,000Y=550,000

Y=22.

So 38-22=16 houses sold for 175,000 and 22 houses for 200,000.

Is this correct?

## Answer This Question

## Related Questions

- Linear equations algebra - a) The sales representative here tells you they also ...
- math - a)The sales representative tells you they also have two floor plans ...
- Algebra - As you are leaving the community, you notice another new community ...
- Algebra 1 - I am kinda confused on this can someone help me? As you are leaving ...
- Algebra - Can somebody help me please? As you are leaving the community, you ...
- Math 116 algebra - There are 38 houses in a new community available with two ...
- Math 116 - As you are leaving the community, you notice another new community ...
- Alegebra, math 116 - 1. Suppose you are in the market for a new home and are ...
- algerbra - 2. As you are leaving the community, you notice another new community...
- algebra - As you are leaving the community, you notice another new community ...

More Related Questions