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March 5, 2015

March 5, 2015

Posted by **Carmen** on Saturday, November 1, 2008 at 7:09pm.

A1) X+Y=38

Q2)Plan 1 sells for $175,000 and plan 2 sells for $200,000. All available houses combined are worth $7,200,000.

What is the equation using same variable from (a).

A2) 175,000X+200,000Y=7,200,000

Q3)Use elimination to determine how many houses in each floor plan available. Explain how you got the answer.

A3) X=38-Y, so you can substitute that into the second equation:

175,000(38-Y)+200,000Y=7,200,000

6,650,000-175,000Y+200,000Y=7,200,000

6,650,000+25,000Y=7,200,000

25,000Y=7,200,000-6,650,000

25,000Y=550,000

Y=22.

So 38-22=16 houses sold for 175,000 and 22 houses for 200,000.

Is this correct?

- Math 116 -
**drwls**, Saturday, November 1, 2008 at 7:16pmYes! Nice work!

- Math 116 -
**jazz**, Saturday, November 1, 2008 at 9:48pmgood job carmen! way to go!

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