Posted by **Carmen** on Saturday, November 1, 2008 at 6:59pm.

I have a long problem which I need help with.....

Q1) there are two plans available with a total of 56 houses available. x represents plan 1 and y represents plan 2. write an equation illustrating the situation:

A1) x+y=56

Q2) there are 3 times as many homes available with the second plan than the first. write an equation illustrating this. use same vaiables as in Q1.

A2) 3x=y

Q3) use the equations from part Q1 & Q2 as a system of equations. Use substitition to determine how many each type of plan is available. describe the steps used to solve the problem.

A3) x + (3x) = 56

4x = 56

x = 56/4

x = 14, and y = 42

Q4) what are the intercepts from part a? (0,56)(56,0) what are the intercepts from part b? (0,0)where would the lines intersect if you solved by graphing? (14,42)

## Answer this Question

## Related Questions

- Math 116 algebra - There are 38 houses in a new community available with two ...
- Alegebra, math 116 - 1. Suppose you are in the market for a new home and are ...
- Math 116 - Q1) there are two plans available, but they only have 38 homes ...
- Math 116 - As you are leaving the community, you notice another new community ...
- Math - a) The sales representative informs you that there are two floor plans ...
- math - The sales representative informs you that there are two floor plans still...
- Math - a) The sales representative informs you that there are two floor plans ...
- Math - a) The sales representative informs you that there are two floor plans ...
- CSU - a) The sales representative informs you that there are two floor plans ...
- Math - I need help,my example: The sales representative say there are two floor ...

More Related Questions