Posted by **masaya** on Saturday, November 1, 2008 at 4:28pm.

Hello. In the class, we did the experiment to calculate the value of Kc for the following reaction:

CH3COOH+CH3CH2OH ĖCH3COOCH2CH3+H2O

we measured the mass for 5 cm^3 of all 5 compound above:

CH3COOH 5.236 g

CH3CH2OH 4.021 g

CH3COOCH2CH3 5.020 g

H2O 5.020 g

HCl 5.098 g

when we titrate 2 mol dm^-3 HCl with the 1 mol dm-^3,10 cm^3 NaOH, the result was 4.85 cm^3.

we used the following mixtures in order to find Kc. We titrated with 1 mol dm^-3 NaOH using phenolphthalein as the indicator.

1) 5 cm^3 HCl, 5 cm^3 CH3COOCH2CH3. titration result 38.8 cm^3

2) 5 cm^3 HCl, 1cm^3 H20, 4 cm^ CH3COOCH2CH3.

titration result 35.7 cm^3

3) 5 cm^3 HCl, 2 cm^3 H2O, 3 cm^3 CH3COOCH2CH3.

titration result 30.2 cm^3

4) 5 cm^3 HCl,3 cm^3 H2O, 2 cm^3 CH3COOCH2CH3.

titration result 37.1 cm^3

5) 5 cm^3 HCl, 4 cm^3 CH3COOCH2CH3, 1 cm^3 CH3CH2OH.

titration result 31.5 cm^3

6) 5 cm^3 HCl, 4 cm^3 CH3COOCH2CH3, 1 cm^3 CH3COOH.

titration result 47.4 cm^3

7) 5 cm^3 HCl, 4 cm^3 CH3CH2OH, 1 cm^3 CH3COOH.

titration result 15.1 cm^3

8) 5 cm^3 HCl, 3 cm^3 CH3CH2OH, 2 cm^3 CH3COOH.

titration result 27.3 cm^3

How do we calculate the value of Kc ?

My teacher told us that the literature value is about 4, but I cannot get the correct/nearly correct answer.

- chemistry -
**DrBob222**, Saturday, November 1, 2008 at 4:37pm
I assume the masses measured were before the experiment started; i.e., what you started with. If so, then change each of these to mols/dm^3.

The titrations were to find the equilibrium concentrations of the components. Use M x dm^3 = #mols,

convert # mols per whatever volume was in the equilibrium mixture, and substitute this value into the Kc expression.

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