Posted by Brandon on Saturday, November 1, 2008 at 2:23pm.
(a) Subtract the potential energy at 23.8 m from the initial kinetic energy.
(KE at highest pt.)
= (initial KE) - M g H
= (0.047 kg)*(54.0 m/s)^2/2
- (0.047)(9.8)(23.80 =
(b) 10.0 m below highest point is 13.8 m above tee elevation. Initial KE is decreased by M*g*13.8 m = 6.4 Joules at that elevation. Use that KE to get the corresponding speed
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