Posted by Brandon on Saturday, November 1, 2008 at 12:41pm.
At the highest point of the jump, the velocity will have only a horizontal component: 11.1 m/s. Since that component is constant, the vertical component when leaving the ramp was
sqrt[(17.9)^2 - (11.1)^2] = 14.0 m/s
The initial vertical velocity component, Vyo, can be used to calculate the maximum height H. The time that the jumper spends going up is
T = Vy,0/g. The average velocity while going up is Vy,o/2. H is the product of those two numbers.
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