Posted by anna on Saturday, November 1, 2008 at 2:56am.
what is the inverse tangent of
(rad3/3)?

trig  Damon, Saturday, November 1, 2008 at 10:33am
30 degrees or pi/6 radians
a 30, 60, 90 triangle is in proportion to
1, sqrt 3, 2
so tan 30 = 1/sqrt 3 *(sqrt 3/sqrt 3) = sqrt 3/3
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