Post a New Question

posted by anna on Saturday, November 1, 2008 at 2:56am.

what is the inverse tangent of (rad3/3)?

30 degrees or pi/6 radians a 30, 60, 90 triangle is in proportion to 1, sqrt 3, 2 so tan 30 = 1/sqrt 3 *(sqrt 3/sqrt 3) = sqrt 3/3

More Related Questions