Posted by **anna** on Saturday, November 1, 2008 at 2:56am.

what is the inverse tangent of

(rad3/3)?

- trig -
**Damon**, Saturday, November 1, 2008 at 10:33am
30 degrees or pi/6 radians

a 30, 60, 90 triangle is in proportion to

1, sqrt 3, 2

so tan 30 = 1/sqrt 3 *(sqrt 3/sqrt 3) = sqrt 3/3

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