Posted by **mikey123** on Friday, October 31, 2008 at 11:45pm.

m=6/7(5,-7)

the equation of the line is y=

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**Sam**, Friday, October 31, 2008 at 11:50pm
Ok, I'm going to try to explain this and let you come to the answer yourself. Feel free to post it so I can check your work and see what you don't understand.

The equation of the line is y = mx + b, where m represents the slope of the line, b is the y intercept (that is, a value on the line where x is equal to 0) and (x,y) are your coordinates.

In order to find the equation of the line, you have to find m or b. In this question, you have to find b given m and a point (x,y).

So you substitute your given values into the equation y = mx + b and solve for b by multiplying m and x and subtracting (or adding depending on the sign) that product from y.

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**mikey123**, Friday, October 31, 2008 at 11:57pm
so is mx the 6/7 or the (5,-7) see this is where it gets confusing for me, I know that The equation of the line is y = mx + b,but how do you find either mx and b

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**Sam**, Saturday, November 1, 2008 at 12:00am
m and x are different values. x is a point on the graph (naturally, on the x axis) and m is the slope. m = 6/7 so your slope is 6/7 and x is 5. y is -7. (x,y) = (5,-7).

You're given m(6/7), x(5), and y(-7). You have to find b by substituting it into the equation and isolating b.

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**Sam**, Friday, October 31, 2008 at 11:53pm
Oh, and once you find b you plug in the values of m and b into the equation and leave x and y for there can be any arbitrary point where you can find y for any values of x and vice versa.

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**mikey123**, Saturday, November 1, 2008 at 12:01am
okay but I need to know what the steps are, for example I have 6/7 and (5,-7) what do I do with these I know they are used to find mx and b, maybe you can show me the steps needed this way once I see how it is done perhaps I can use the same method for other problems.

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