Posted by james on Friday, October 31, 2008 at 12:09pm.
CuSO4.5H2O ==> Cu^+2 + SO4^- + 5H2O
Convert 3.70 g CuSO4.5H2O to mols CuSO4.5H2O. Then for each mol of the starting material, you obtain 1 mol Cu^+2 ions and 1 mol SO4^-2 ions. Add those together to find the total mols. I've not added the H2O since that doesn't ionize (at least not that much).
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