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December 21, 2014

Homework Help: Chemistry.

Posted by Vanessa on Friday, October 31, 2008 at 11:45am.

hi again, thanks to the previous help i got the first part of the question. the second part builds on the first part as we used that stock solution for titration of the next. we are now given:

Concentration of Standard Acid Soultion (M) = 0.100 M

Volume of Standard Acid Solution (mL) = 25.00 mL

Volume oof Stock Solution of NaOH (mL) = 18.65 Ml

Concentration of Stock Solution of NaOH (M) = 0.108 M (from previous question asked)

Now it is asking for the concentration of the stock solution.

Would you just do this:

0.100M X 0.025 L = ?? mols

and then ?? mols / 18.65 mL?

is that how to do it or is there more processes involved?

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