Posted by ben on Friday, October 31, 2008 at 2:27am.
Ba(OH)2.8H2O ==>Ba^+2 + 2OH^- + 8H2O
How many mols of the compound did you start with initially. That will be 30.2 g Ba(OH)2.H2O/molar mass of that material.
Then you get 1 mol Ba^+, + 2 mols OH^- + 8 mols H2O. Add them to get total mols. The question may or may not be a trick question. Note that it asks for the total moles of IONS. If that is the intent of the problem, then the 8 mols H2O aren't included in the total since they are not ions.
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