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March 29, 2015

March 29, 2015

Posted by **dt** on Friday, October 31, 2008 at 12:15am.

- HS Calculus/math -
**drwls**, Friday, October 31, 2008 at 9:14amSolve this equation for n, the number of years:

4000 = 7500 * (0.75)^n

4000/7500 = 0.5333 = 0.75^n

n = (log 0.5333)/(log 0.75)

It will take a bit more than 2 years.

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