Posted by Grant on Thursday, October 30, 2008 at 8:51am.
A force of 23.0 N is required to start a 3.1 kg box moving across a horizontal concrete floor.
(a) What is the coefficient of static friction between the box and the floor?
(b) If the 23.0 N force continues, the box accelerates at 0.50 m/s2. What is the coefficient of kinetic friction?
How do I find the answer to part b?

Physics  bobpursley, Thursday, October 30, 2008 at 8:55am
applied forcefriction=mass*acceleration
solve for friction, then set it equal to mu*mg and solve for mu.

Physics  Grant, Thursday, October 30, 2008 at 5:07pm
so i would do.. 23N  friction= 3.1(or 30.38N) *.5
and get f=7.81
then 7.81 = mu k * mu g ?
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