Post a New Question

Physics

posted by on .

A force of 23.0 N is required to start a 3.1 kg box moving across a horizontal concrete floor.
(a) What is the coefficient of static friction between the box and the floor?

(b) If the 23.0 N force continues, the box accelerates at 0.50 m/s2. What is the coefficient of kinetic friction?



How do I find the answer to part b?

  • Physics - ,

    applied force-friction=mass*acceleration
    solve for friction, then set it equal to mu*mg and solve for mu.

  • Physics - ,

    so i would do.. 23N - friction= 3.1(or 30.38N) *.5

    and get f=7.81

    then 7.81 = mu k * mu g ?

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question