3x^2 - 11x + 6 = 0
x=3; x=0.6666666666
Are you at the stage where you are solving quadratics by factoring them??
if so, then it factors to
(3x+2)(x-3) = 0
then x = -2/3 or x = 3
@ Reiny: your answer is wrong. It should be this:
(3x-2)(x-3) = 0
So, x=3; x=2/3 or 0.6666666
Have fun!
To solve the quadratic equation 3x^2 - 11x + 6 = 0, we can use the quadratic formula.
The quadratic formula is x = (-b ± √(b^2 - 4ac)) / (2a), where a, b, and c are the coefficients of the quadratic equation ax^2 + bx + c = 0.
Comparing our equation 3x^2 - 11x + 6 = 0 to the general quadratic equation form, we can see that a = 3, b = -11, and c = 6.
Plugging these values into the quadratic formula, we get:
x = (-(-11) ± √((-11)^2 - 4 * 3 * 6)) / (2 * 3)
x = (11 ± √(121 - 72)) / 6
x = (11 ± √49) / 6
Now we can simplify further:
x = (11 ± 7) / 6
This gives us two possible solutions:
1) x = (11 + 7) / 6 = 18 / 6 = 3
2) x = (11 - 7) / 6 = 4 / 6 = 2/3
Therefore, the solutions to the quadratic equation 3x^2 - 11x + 6 = 0 are x = 3 and x = 2/3.