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November 27, 2014

November 27, 2014

Posted by **jennifer** on Wednesday, October 29, 2008 at 2:38pm.

- intro to statistics -
**drwls**, Wednesday, October 29, 2008 at 3:50pmUsing a normal distribution function, select the value of x(mean) that makes the probability integral of P(x) from x = 0 to 8.0 equal to 0.99, when sigma = 0.03

- intro to statistics -
**drwls**, Wednesday, October 29, 2008 at 5:25pmYou may find the JAVA tool at this website for problems of this type.

http://psych-www.colorado.edu/~mcclella/java/normal/accurateNormal.html

I used it to get an answer of 7.93 oz.

Enter mean of 7.93, sigma = 0.03 and the range of P(x) 0 to 8.0 oz, and you get a probability of 0.990

- intro to statistics -
**Brad**, Sunday, March 11, 2012 at 6:01pmUse Norminv in excel(%, cup size, stanard dev ) then round to the 2nd decimal

hope this helpful

- intro to statistics -
**stacy**, Friday, March 23, 2012 at 5:38pmFind the z-value with a right tail of 1%: z = 2.3263

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Find the x-value using x = zs+u

x = 2.3263*0.01+8 = 8.0233

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Let that be the mean amount of coffee to be dispensed

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