Calculus
posted by Anonymous .
Consider the equation:
x^2  2xy + 4y^2 = 64
Write an expression of the slope of the curve at any point.
(y^p)= y prime
My work
2x  2(xy^p + y) + 8yy^p = 0
2x 2xy^p  2y + 8yy^p = 0
2xy^p + 8yy^p = 2y 2x
factored out y^p and then divided to get
(2y  2x) / (8y  2x)
Which I think is wrong.
Please let me know where I went wrong if I did.

I would reduce it to
y'=(yx)/(4yx) 
Ok, so it was right at first. Thanks for the further simplifying. :)