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Calculus

posted by on .

Consider the equation:

x^2 - 2xy + 4y^2 = 64

Write an expression of the slope of the curve at any point.

(y^p)= y prime

My work

2x - 2(xy^p + y) + 8yy^p = 0

2x -2xy^p - 2y + 8yy^p = 0

-2xy^p + 8yy^p = 2y -2x

factored out y^p and then divided to get

(2y - 2x) / (8y - 2x)

Which I think is wrong.

Please let me know where I went wrong if I did.

  • Calculus - ,

    I would reduce it to

    y'=(y-x)/(4y-x)

  • Calculus - ,

    Ok, so it was right at first. Thanks for the further simplifying. :)

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