Posted by **Anonymous** on Wednesday, October 29, 2008 at 1:46pm.

Consider the equation:

x^2 - 2xy + 4y^2 = 64

Write an expression of the slope of the curve at any point.

(y^p)= y prime

My work

2x - 2(xy^p + y) + 8yy^p = 0

2x -2xy^p - 2y + 8yy^p = 0

-2xy^p + 8yy^p = 2y -2x

factored out y^p and then divided to get

(2y - 2x) / (8y - 2x)

Which I think is wrong.

Please let me know where I went wrong if I did.

- Calculus -
**bobpursley**, Wednesday, October 29, 2008 at 1:52pm
I would reduce it to

y'=(y-x)/(4y-x)

- Calculus -
**Anonymous**, Wednesday, October 29, 2008 at 1:57pm
Ok, so it was right at first. Thanks for the further simplifying. :)

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