Physics
posted by Brandon on .
A rescue helicopter lifts a 65 kg person straight up by means of a cable. The person has an upward acceleration of 0.70 m/s2 and is lifted from rest through a distance of 13 m.
(a) What is the tension in the cable?
N
(b) How much work is done by the tension in the cable?
J
(c) How much work is done by the person's weight?
J
(d) Use the workenergy theorem and find the final speed of the person.
m/s

The tension is mg+ma
The work done by tension is tension*13
work done by weigh? mg*13
worktension=changePE+KEchange
solve for KE change, then velocity from that. 
How do you solve for KE change?
Work done by weight 65*9.8*13= 8281 right?