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Posted by on Wednesday, October 29, 2008 at 1:41pm.

A rescue helicopter lifts a 65 kg person straight up by means of a cable. The person has an upward acceleration of 0.70 m/s2 and is lifted from rest through a distance of 13 m.
(a) What is the tension in the cable?
N
(b) How much work is done by the tension in the cable?
J
(c) How much work is done by the person's weight?
J
(d) Use the work-energy theorem and find the final speed of the person.
m/s

  • Physics - , Wednesday, October 29, 2008 at 1:45pm

    The tension is mg+ma
    The work done by tension is tension*13
    work done by weigh? mg*13
    worktension=changePE+KEchange
    solve for KE change, then velocity from that.

  • Physics - , Wednesday, October 29, 2008 at 2:12pm

    How do you solve for KE change?
    Work done by weight- 65*9.8*13= 8281 right?

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