A rescue helicopter lifts a 65 kg person straight up by means of a cable. The person has an upward acceleration of 0.70 m/s2 and is lifted from rest through a distance of 13 m.
(a) What is the tension in the cable?
(b) How much work is done by the tension in the cable?
(c) How much work is done by the person's weight?
(d) Use the work-energy theorem and find the final speed of the person.
Physics - bobpursley, Wednesday, October 29, 2008 at 1:45pm
The tension is mg+ma
The work done by tension is tension*13
work done by weigh? mg*13
solve for KE change, then velocity from that.
Physics - Brandon, Wednesday, October 29, 2008 at 2:12pm
How do you solve for KE change?
Work done by weight- 65*9.8*13= 8281 right?