Posted by Marysia on Wednesday, October 29, 2008 at 10:26am.
I am currently doing a lab write up and i have a little problem with some ionic equations
the question goes as follows:
You are provided with aqueous solutions of CaCl2, AlCl3, ZnCl2, CuCl2, FeCl2 and FeCl3 in six separate test tubes. To each of the solutions add 2-3 drops of dilute NH3 solution. Record your observations and illustrate changes observed with an ionic equation. Then continue to add NH3 solution until it is in excess.Record any changes observed.
AlCl3-white ppt, insoluble in excess
Zncl2-white ppt, soluble in excess
CuCl2- light blue ppt, soluble in excess
FeCl2-dirty green ppt, insoluble in excess
FeCl3-red brown ppt, insoluble in excess
so the first ionic equation would be
Ca^2+ + 2Cl^- + N^3- +3H^+ yielding the same products right?
but then what will happen to the rest
will the products of the second one for example be AlN or Al(OH)3 ?
Could you please help me with the remaining ionic equations??
- Chemistry - bobpursley, Wednesday, October 29, 2008 at 10:35am
By adding the NH3 solution (actually NH4OH), you are creating...
NH4+ and OH-
so you add those two ions to the metal and chloride ions. YOu know the product of ammonium and chloride will be soluble, so any insoluble product will be the metal oxide compound, for instance, aluminum hydroxide.
On your results, calcium hydroxide is not very soluble, so if there were plenty of calcium chloride, you should have gotten a ppt when in excess.
- Chemistry - Marysia, Wednesday, October 29, 2008 at 10:40am
Oh and i have on emore question
for the CuCl2 example i've done some research and what i came up with is
[Cu(NH3)4(H2O)2]^2+, but this product is aqueous and i need to find the temporary ppt that was produced before i added excess NH3 solution
sorry for more complications...
- Chemistry - Marysia, Wednesday, October 29, 2008 at 10:45am
okay thanks bobpursely
that explains a lot
and regarding the CaCl2 and CaOH ppt, i think there was a slight ppt but my teacher let me ignore it so i guess im going to stick to the no ppt result
thanks a lot for helping
- Chemistry - bobpursley, Wednesday, October 29, 2008 at 10:45am
Yes, you can form that complex, in dilute concentrations. Is Cu(OH)2 the right color?
- Chemistry - Marysia, Wednesday, October 29, 2008 at 10:48am
i think i can ignore the complex, because the question is asking for the eqation before i add excess and so i only nees to write an equation for the ppt
but i'm just curious could the other metals also form complexes like the Cu does?
- kujc mzgpoiw - kujc mzgpoiw, Sunday, February 1, 2009 at 8:19pm
khzyxrtn csuma mjvsfozt nbthsfgm sdpvncqbl fiztn rtons
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