Posted by **Confused** on Tuesday, October 28, 2008 at 10:29pm.

A box moves down a conveyor belt the is angled at 15 degrees, at a rate of 6m/s. The box then enters a dump off that is 3m below the end of the belt, what is the horizontal distance between the dump off and the belt?

I have no idea where to start with this...I know you have x and y components of something but I don't know what to do...any help in the right direction would be appreciated.

- physics -
**bobpursley**, Tuesday, October 28, 2008 at 10:42pm
:You have to figure the time it took to fall 3m. It had an initial vertical velocity downward of -6sin15.

h=vi*t -4.9t^2

solve for t.

Then, you know the intial horizontal velocity is 6cos15, and the time, so what distance did it travel horizontally?

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