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A box moves down a conveyor belt the is angled at 15 degrees, at a rate of 6m/s. The box then enters a dump off that is 3m below the end of the belt, what is the horizontal distance between the dump off and the belt?

I have no idea where to start with this...I know you have x and y components of something but I don't know what to do...any help in the right direction would be appreciated.

  • physics -

    :You have to figure the time it took to fall 3m. It had an initial vertical velocity downward of -6sin15.

    h=vi*t -4.9t^2
    solve for t.

    Then, you know the intial horizontal velocity is 6cos15, and the time, so what distance did it travel horizontally?

  • physics -

    You can't solve for t from that though can you? If you use quadratic equation its a negative sign under the root and you can't take the root of that. I'm confused:S

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