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September 1, 2014

Homework Help: chemistry/please double check

Posted by Joshua on Tuesday, October 28, 2008 at 8:02pm.

Hi, I just need to know if I finally got this exercise right.

Calculate the amount of heat in kilojoules released when 50 grams of steam at 125 Celsius are converted to 50 grams of ice at -125 Celsius.

so,

qw= 50*4.184J/g C (125 C-o)= 26.15 x 10^3

qi= 50*2.09*(-125)=-13.065 KJ

q= 50*1.860 (-125)= -11.63 KJ

q1+q2=q3= -11.92 kJ

please let me know if this way is correct thanks

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