Posted by **Jill** on Tuesday, October 28, 2008 at 3:30pm.

How would you solve these types of problems? They confuse me!

1. Write the quation of the line that passes through points (-8,-6) and (5,3)

2. Write the equation of the line that passes through (3,-4) and has a slope of 2.

I know that you have to do something with y=mx+b, but I don't know what. I also have a graphing calcluator if that helps with anything.

- Algebra -
**drwls**, Tuesday, October 28, 2008 at 4:05pm
1. The slope of the line will be

m = (y2-y1)/(x2-x1) = 9/13

The equation will have the form

y-y1 = m(x-x1)

Use x1, y1, and rewrite this as:

y+6 = (9/13)(x+8)

y = (9/13)x -6/13

The same approach will work for #2

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