Algebra
posted by Jill on .
How would you solve these types of problems? They confuse me!
1. Write the quation of the line that passes through points (8,6) and (5,3)
2. Write the equation of the line that passes through (3,4) and has a slope of 2.
I know that you have to do something with y=mx+b, but I don't know what. I also have a graphing calcluator if that helps with anything.

1. The slope of the line will be
m = (y2y1)/(x2x1) = 9/13
The equation will have the form
yy1 = m(xx1)
Use x1, y1, and rewrite this as:
y+6 = (9/13)(x+8)
y = (9/13)x 6/13
The same approach will work for #2 
how did you get from
y+6 = (9/13)(x+8)
to
y = (9/13)x 6/13 ?