Posted by **Michelle** on Monday, October 27, 2008 at 11:01pm.

Are my answers right? If they are wrong you dont have to tell me how to do it its okay =)

A particle starts at time t=0 and moves along the x-axis so that its position at any time t(greater or equal to) 0 is given by x(t)=(t-1)^3 (2t-3)

1.find the velocity of the particle at any time t(greater or equal to) 0

2.for what values of t is the velocity of the particle less than zero?

3.find the value of t when the particle is moving and the acceleration is zero

My Answers:

1.(6t-9)(t-1)^2 + 2(t-1)^3

2.t(less than or equal to) 1

3.t=1

- Calculus (Answer Check) -
**jacky**, Wednesday, July 21, 2010 at 10:15pm
P1=(-3,2);P2=(-6,-2)

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