Posted by Michelle on Monday, October 27, 2008 at 11:01pm.
Are my answers right? If they are wrong you don't have to tell me how to do it its okay =)
A particle starts at time t=0 and moves along the xaxis so that its position at any time t(greater or equal to) 0 is given by x(t)=(t1)^3 (2t3)
1.find the velocity of the particle at any time t(greater or equal to) 0
2.for what values of t is the velocity of the particle less than zero?
3.find the value of t when the particle is moving and the acceleration is zero
My Answers:
1.(6t9)(t1)^2 + 2(t1)^3
2.t(less than or equal to) 1
3.t=1

Calculus (Answer Check)  jacky, Wednesday, July 21, 2010 at 10:15pm
P1=(3,2);P2=(6,2)
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