Posted by Lucy on .
Hi, I need a little help with solving this question for c:
(2c1)^3=4c^21
I did this already:
(2c1)^3(4c^21)=0
(2c1)^3(2c+1)(2c1)=0
But I need help with the next steps... Thank you!

Math 
Reiny,
(2c1)^3(2c+1)(2c1)=0
good so far, now take out a common factor
(2c1)[(2c1)^2  (2c+1)] = 0 expand and simplify to
(2c1)(4c^2  6c) = 0
(2c1)(c)(4c6) = 0
c = 1/2 or c = 0 or c = 3/2