is this the right anser? for this problem please let me know thanks

calculate the amount of heat in kilojoules released when 50 grams of steam at 125 C are converted to 50 grams of ice at -125 C

so

50 grams of H2O
Ti= 124 C
Tf= -125 C
q=? J=?

q=m *Cp * At

J= 50g * 4.184J/g C= (-125 C - 125 C) =2.1 x 10^2 j

is this the right? please let me know thanks

no. I answered this before, and you did not do it the suggested way.

http://www.jiskha.com/display.cgi?id=1225111405

To calculate the amount of heat released when 50 grams of steam at 125°C are converted to 50 grams of ice at -125°C, we can use the formula for heat transfer:

q = m * Cp * ΔT

where:
q is the amount of heat transferred in joules (J)
m is the mass of the substance in grams (g)
Cp is the specific heat capacity of the substance in J/g°C
ΔT is the change in temperature in °C

First, we need to calculate the change in temperature (ΔT) by subtracting the initial temperature (Ti) from the final temperature (Tf):

ΔT = Tf - Ti = (-125°C) - (125°C) = -250°C

Now let's calculate the amount of heat released:

q = 50g * 4.184J/g°C * (-250°C) = -52,300 J

However, there seems to be a mistake in your calculations. The specific heat capacity of water (Cp) is approximately 4.184 J/g°C, not 4.184 J/gC. Additionally, the change in temperature should be -250°C, not -125°C - 125°C.

Therefore, the correct answer is:

q = 50g * 4.184J/g°C * (-250°C) = -52,300 J

It is important to note that the answer is negative because heat is being released (exothermic process) in this case. To convert to kilojoules (kJ), divide the answer by 1000:

q = -52,300 J / 1000 = -52.3 kJ

So, the correct amount of heat released when 50 grams of steam at 125°C are converted to 50 grams of ice at -125°C is -52.3 kJ.