Wednesday

July 30, 2014

July 30, 2014

Posted by **elley** on Sunday, October 26, 2008 at 9:49pm.

y= 72-30(0.98)^t

Answer the question by interpreting y adn dy/dt.

1. what is the temperature of the refrigerator? how can you tell?

2. what is the temperature of the room? how can you tell?

3. when is the milk warming up the fastest? how can you tell?

4. determine algebraically when the temperature of the milk reaches 55F(degree)

5. at what reate is the ilk warming when its temperature is 55F(degree)? answer with an appropriate unit of measure.

- Calculas HS -
**Damon**, Sunday, October 26, 2008 at 10:17pm1. When t = 0, we are at refrigerator temp

anything^0 = 1

72 - 30 = 42

2. when t gets big, the second term gets vanishingly small so Troom = 72

3. dy/dt = -30 *.98^t * ln(.98)

= .606 * .98^t

That is maximum (.606) when t = 0 because .98 is less than 1

4. 55 = 72 - 30*.98^t

- 17 = -30 *.98^t

.98^t = .5667

t ln .98 = ln .5667

t = -.568/-.0202 = 28.1 minutes

5. dy/dt = .606 * .98^t

.606 * .98^28.1

= .343 degrees/minute

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