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November 26, 2014

November 26, 2014

Posted by **Nathaniel** on Sunday, October 26, 2008 at 8:48pm.

so far i have the formula and the derivative.

A=.5absin(theta)

A'=.5abcos(theta)

then i set the derivative to zero in order to get the critical point, but i don't know how to solve it because if I divide zero by .5, it will just be 0.

0=.5abcos(theta)

can anyone help me get past this step? thanks.

- math-calc -
**drwls**, Sunday, October 26, 2008 at 9:07pmIf A' = 0, and a and b are fixed positive numbers, then cos (theta) = 0 and theta = 90 degrees.

The answer seems intuitively correect.

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