Posted by **Nathaniel** on Sunday, October 26, 2008 at 8:21pm.

Two sides of a triangle have constant lengths a and b, and the angle between them is theta. What value of theta will maximize the area of the triangle?

so far i have the formula and the derivative.

A=.5absin(theta)

A'=.5abcos(theta)

then i set the derivative to zero in order to get the critical point, but i don't know how to solve it because if I divide zero by .5, it will just be 0.

0=.5abcos(theta)

can anyone help me get past this step? thanks.

- Calculus -
**charles**, Monday, October 27, 2008 at 12:05am
you almost in there already, think about the cos(theta) = 0, it means the theta=90 degree, so, you got it

## Answer this Question

## Related Questions

- math-calc - Two sides of a triangle have constant lengths a and b, and the angle...
- Pre-Calculus - Two sides of a triangle are x units and y units in length. The ...
- Pre-Calculus - Two sides of a triangle are x units and y units in length. The ...
- calculus - show that the area(A) of an isosceles triangle, whose equal sides are...
- trig - Find csc(theta), tan (theta), and cos (theta), where theta is the angle ...
- calculus - a trapezoid is a quadrilateral with (only) two sides (called bases) ...
- math - Hi ! Here is my question: The pythagorean theorem gives the relationships...
- math - Two sides of a triangle have lengths 15 m and 18 m. The angle between ...
- related rates with work shown - this is a relate rates problem in calculus in a ...
- Precalculus - In most geometry courses, we learn that there's no such thing as "...