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August 1, 2014

August 1, 2014

Posted by **Nathaniel** on Sunday, October 26, 2008 at 8:21pm.

so far i have the formula and the derivative.

A=.5absin(theta)

A'=.5abcos(theta)

then i set the derivative to zero in order to get the critical point, but i don't know how to solve it because if I divide zero by .5, it will just be 0.

0=.5abcos(theta)

can anyone help me get past this step? thanks.

- Calculus -
**charles**, Monday, October 27, 2008 at 12:05amyou almost in there already, think about the cos(theta) = 0, it means the theta=90 degree, so, you got it

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