posted by tomi .
a mixture is prepared using equal masses of two volatile liquid benzene, C6H6 and ethanol C2H5OH. what is the mole fraction of benzene in this mixture?
I would pick a number for the masses.
The convert masses to mols.
mols fraction X = molsX/total # of mols.
Post your work if you get stuck.
DrBob222 you are the best thanks for all you help...you great. thanks
ok, so I assumed the masses to equal 5.00 g
molar mass of benzene is =78.12 g/mol
molar mass of ethanol is =46.08g/mol
moles of C6H6=
moles of C2H5OH=
so mole fraction of benzene should equal to=
so the mole fraction of benzene is 0.371 mol
Is my approach to the problem correct?