There are six books in a stack, and each book weighs 5N. The coefficient of friction between the books is 0.2. With what horizontal force must one push to start sliding the top five books off the bottom one?

I got 7N, but i think it is wrong. How can I solve it right??

let mu be the coeff of friction.

mu(5*5N)=Force

i have a question in here, what is the friction coefficient between the books and the table if those books sit on the table.

I really,really need help. Please?

he's definitely out of school, let's hope he's not stuck on the same question

To solve this problem, you need to consider the forces acting on the books. There are two main forces involved: the force of friction and the force required to start sliding the top five books off the bottom one.

First, let's calculate the force of friction between the books. The force of friction can be found using the equation:

Frictional force = coefficient of friction × normal force

The normal force is the total weight of the books above the bottom book. Since each book weighs 5N and there are five books above the bottom one, the normal force is:

Normal force = 5N/book × 5 books = 25N

Plugging in the given coefficient of friction (0.2), we find:

Frictional force = 0.2 × 25N = 5N

Now, to start sliding the top five books off the bottom one, a force greater than the frictional force is required. The actual force required is the sum of the frictional force and the weight of the top five books, since we are pushing against gravity as well:

Force required = Frictional force + (Weight of top five books)
= Frictional force + (5N/book × 5 books)
= 5N + 25N
= 30N

Therefore, the correct answer is 30N, not 7N.

it is 7