Posted by TAG on Sunday, October 26, 2008 at 6:37pm.
The acceleration of gravity at the surface of a planet (or any spherical object) with mass M and radius R is proportional to M/R^2. To compare it to the Earth's value of g, multiply by (M/Mearth)/(R/Rearth)^2
For Mars, that ratio is (0.11)/0.53)^2 = 0.39
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