10-5=3y
2x-3y=1
i am totally lost help please
This is a system of equations
divide by 3 on the first to get
y=10/3-5/3 then put that in for y on the other equation to get x, and you have solved the system of equations x=(whatever) and y=(whatever).
You have a typo in the first equation, no x term
re-write the second one as
2 x - 1 = 3 y
then you have whatever your first equation was supposed to be = 2 x - 1
since they are both equal to 3y
solve for x
then go back and get y
Sure, I can help you solve this set of equations.
To begin, we have two equations:
Equation 1: 10 - 5 = 3y
Equation 2: 2x - 3y = 1
First, let's simplify Equation 1:
10 - 5 = 3y
5 = 3y
Now let's move to Equation 2 and substitute the value of 'y' from Equation 1:
2x - 3y = 1
2x - 3(5/3) = 1 <-- Substituting y = 5/3 from the previous equation
Next, simplify Equation 2:
2x - (15/3) = 1
2x - 5 = 1
Now, let's solve Equation 2 for 'x':
2x - 5 = 1
2x = 6
x = 3
So, the solution to the system of equations is x = 3 and y = 5/3. Both equations are satisfied by these values.
To solve these types of equations, you need to isolate either 'x' or 'y' in one equation and substitute it into the other equation. Then, you can solve for the remaining variable.