Posted by **Lucy** on Sunday, October 26, 2008 at 3:41pm.

I have a question about the symmetry of graphs, but maybe it's more of a simple factoring question...

Why is f(x)=x+(1/x) odd, while h(x)=x-x^2 is neither even nor odd?

I understand that f(-x)=-x-1/x=-(x+1/x)=-f(x) is odd because f(x)=f(-x).

Then for h(-x)=-x-x^2...why can't you factor out the negative in this question like the previous one? But my textbook leaves it like this and says it's neither even nor odd...

## Answer this Question

## Related Questions

- math - I know It's probably an easy question but I don't know remember how to do...
- odd and even functions - Using f is odd if f(-x) = -f(x) or even if f(-x) = f(x...
- Symmetry - For these functions, determine which ones are NEITHER even nor odd. A...
- math - what will i answer if the question is " identify the symmetry" is it even...
- Calculus, check my answer, please! 1 - Did I get this practice question right? 1...
- Algebra - Let f(x) = 1 – 3x^2. Which of the following is true? Give a brief ...
- Algebra - Confused Please Help! Thanks! Let f(x) = 1 – 3x^2. Which of the ...
- Algebra - Let f(x) = 1 – 3x^2. Which of the following is true? Please give us a ...
- Algebra - Let f(x) = 1 – 3x^2. Which of the following is true? Give a brief ...
- Calculus - Determine if function is even, odd, or neither... f(x) = secx tanx I ...

More Related Questions