Math (precalculus)
posted by Lucy on .
I have a question about the symmetry of graphs, but maybe it's more of a simple factoring question...
Why is f(x)=x+(1/x) odd, while h(x)=xx^2 is neither even nor odd?
I understand that f(x)=x1/x=(x+1/x)=f(x) is odd because f(x)=f(x).
Then for h(x)=xx^2...why can't you factor out the negative in this question like the previous one? But my textbook leaves it like this and says it's neither even nor odd...

h(x) = x  x^2
h(x) = x x^2
but x is not x so that part is odd
while x^2 is x^2 so that part is even
for odd I needed
h(x) = x + x^2 = (xx^2)
for even I needed
h(x) = x  x^2