Posted by Alexandria on Sunday, October 26, 2008 at 2:22pm.
x^3 y^-2 / [ x^-2 y^4]
3 - -2 = 5
-2 -4 = -6
so
x^5 y^-6
2 x^-2 ( 3 x^4 - 6 x^2 )
-2+4 = 2
-2 +2 = 0 remember anything^0 = 1
so
6 x^2 -12 x^0 = 6 x^2 -12
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