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October 1, 2014

October 1, 2014

Posted by **Alexandria** on Sunday, October 26, 2008 at 2:22pm.

x to the third power y to the negative two power/x to the negative two power times y to the fourth power=

2x to the neg. second power (3x to the fourth - 6x to the econd)=

(-2x to the third)(-3x to the neg second) both expressions to the neg second

(2x to the second y to the negative second) to the third power

(2x to the negative fifth y to the fourth) to the third

Thank you your help is genuinely appreciated.

- Algebra -
**Damon**, Sunday, October 26, 2008 at 2:34pmx^3 y^-2 / [ x^-2 y^4]

3 - -2 = 5

-2 -4 = -6

so

x^5 y^-6

2 x^-2 ( 3 x^4 - 6 x^2 )

-2+4 = 2

-2 +2 = 0 remember anything^0 = 1

so

6 x^2 -12 x^0 = 6 x^2 -12

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