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Posted by on Saturday, October 25, 2008 at 8:55pm.

A 2.0kg bag is held by a string to the ceiling. A 10g bullet travelling at 200m/s strikes the stationary bag. The height of the bag after the collision is 10cm, assuming there is no friction, determine the speed, in m/s, of the bag after the collision.

  • Physics...not sure what formula to use - , Sunday, October 26, 2008 at 2:12am

    mb = mass of bullet
    vb = velocity of bullet
    ma = mass of bag
    vab = velocity of bag and bullet
    from conservation of momentum:
    mb*vb = (ma + mb)*vab
    then from conservation of energy:
    (ma + mb)*vab^2/2 = (ma + mb)*g*h

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