algebra  Help!
posted by Kate on .
The local fish market is having a sale on whole fish. the prices are as follows:
You can buy an albacore and a barracuda for$21
You can buy a barracuda and a carp for $32
You can buy a carp and a dogfish for $32
You can buy a dogfish and an eel for $37
You can buy an eel and flounder for $31
You can buy a flounder and a gar for $25
You can buy gar and an albacore for $26
Determine the cost of each individual fish

I gave a method a few minutes ago.

Price list:
Albacore $12
Barracuda $9
Carp $15
Dogfish $17
Eel $20
Flounder $11
Gar $14
Proof: Call the fish AG and make all the prices into simple addition equations.
Add all the numbers and equations together. You get:
2(A+B+C+D+E+F+G) = 196.
And thus,
(A+B+C+D+E+F+G) = 98
After that, add together the first, third, fifth, and seventh equations.
(A+B+C+D+E+F+G+A) = 110
And then subtract the last two equations I've written from each other, leaving...
A = 12.
After that, it's a matter of simple addition i know this is late 
Thank you Unknown Guy, helped a lot!