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algebra - Help!

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The local fish market is having a sale on whole fish. the prices are as follows:

You can buy an albacore and a barracuda for$21
You can buy a barracuda and a carp for $32
You can buy a carp and a dogfish for $32
You can buy a dogfish and an eel for $37
You can buy an eel and flounder for $31
You can buy a flounder and a gar for $25
You can buy gar and an albacore for $26

Determine the cost of each individual fish

  • See reply to Brandon above -

    I gave a method a few minutes ago.

  • algebra - Help! -

    Price list:
    Albacore $12
    Barracuda $9
    Carp $15
    Dogfish $17
    Eel $20
    Flounder $11
    Gar $14

    Proof: Call the fish A-G and make all the prices into simple addition equations.

    Add all the numbers and equations together. You get:

    2(A+B+C+D+E+F+G) = 196.

    And thus,

    (A+B+C+D+E+F+G) = 98

    After that, add together the first, third, fifth, and seventh equations.

    (A+B+C+D+E+F+G+A) = 110

    And then subtract the last two equations I've written from each other, leaving...

    A = 12.

    After that, it's a matter of simple addition i know this is late

  • algebra - Help! -

    Thank you Unknown Guy, helped a lot!

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