Posted by mike on .
A aeroplane with a mass of 9940 kg completes a vertical loop of radius 596m with a speed of 155m/s. What normal force does the airplane seat exert on the 92 kg pilot at the top of the loop and at the bottom of the loop?

physics 
drwls,
Centripetal force = M v^2/R = Weight +/ (seat force)
A + sign applies at the top of the loop and a minus sign applies at the bottom.
The weight is M g. M is the pilot's mass. The airplane's mass does not matter. Solve for the seat force 
physics 
Damon,
Thank you for giving both speed and radius this time:
Ac = v^2/r
at the top
force on seat = m (v^2/r  g)
= 92 (155^2/596 9.8)
= 2806 N
at the bottom
m (v^2/r + g)
=92 (155^2/596 +9.8) = 4610 N