A block slides down a frictionless plane having an inclination of 14.3°.
If the block starts from rest at the top and the length of this incline is 1.77 m, find the acceleration of the block.
The component of the weight force in the direction down the ramp is
F = M g sin 14.3
Set this equal to M a and solve for the acceleration, a. This works because there is no friction to consider.
Note that the mass M cancels out.
The length of the incline is information that is not needed.
o...the length of the incline is needed for the next question, which i need help with as well
it asks what is the the velocity at the bottom of the incline?
how would u figure this out? what formula would u use (if any)?
To find the acceleration of the block, we can use the equation of motion for an object sliding down an inclined plane.
The equation is:
a = g * sin(θ)
Where:
a = acceleration
g = acceleration due to gravity (approximately 9.8 m/s^2)
θ = inclination angle of the plane (14.3° in this case)
To find the acceleration, we need to first convert the angle from degrees to radians.
θ(in radians) = θ(in degrees) * π / 180
Substituting the values, we get:
θ(in radians) = 14.3° * π / 180 = 0.249 rad
Now we can calculate the acceleration by substituting the values into the equation:
a = g * sin(θ) = 9.8 m/s^2 * sin(0.249 rad) ≈ 1.43 m/s^2
Therefore, the acceleration of the block is approximately 1.43 m/s^2.