Posted by steve Alexander on Friday, October 24, 2008 at 7:24pm.
For the max height, energy thinking
top PEnergy = intial PE + Initial Kenergy
mgh=mg*14.7 + 1/2 m 245^2
solve for h, the maximum height.
when is it attained?
h=14.5+245t -1/2 g t^2 for h max, solve for time t.
when it reaches the ground?
h=0 solve for time.
The 4.9 is a fixed constant and deals with the force of gravity on earth.
Your equation would be
s = -4.9t^2 + 245t + 14.7
take the derivative set it equal to zero and solve for t
put that t back into the equation to find the maximum height
b) when it hits the ground, s = 0
so solve 0 = -4.9t^2 + 245t + 14.7 for t
great job
Related Questions
math - If an object is fired upward from the top of a tower at a velocity of 80 ...
Physics - A test rocket is launched vertically from ground level (y=0m), at time...
Physics 221 - 1. throughout a time interval, while the speed of a particle ...
physics - How high will an object rise if it is projected upward at a 45 degree ...
physics - How high will an object rise if it is projected upward at a 45 degree ...
Physics - An object is thrown vetically upward with an initial velocity of 14.7 ...
Physics (last question) - A 800 kg projectile is fired vertically upward with an...
physics - A ball is thrown upward. It leaves the hand with a velocity of 13.8 m/...
Physics - A thin, uniform rod is hinged at its midpoint. To begin with, one half...
college - a ball is thrown vertically upward from the ground with the velocity ...
For Further Reading