Posted by **steve Alexander** on Friday, October 24, 2008 at 7:10pm.

i just want to know form where i got on this formula the 4.9tē on this formula s=4.9tē+Vot+h because the book only say that a physics theory shows that when an object is thrown upward with an initial velocity Vo, its approximate height is given by that quadratic function

i will appreciate if you can explain me that because i have a math problem that uses that equation but i don't know from wheres that 4.9tē

- math and physics -
**bobpursley**, Friday, October 24, 2008 at 7:17pm
It comes from calculus, and I assume you do not know that.

Newton found the velocity of a falling object was proportional to the time it fell.

vincreased= constant*time

but the constant we now call g, 9.8m/s^2, which comes from his universal gravitational equation.

From this, we get

Vfinal=vinitial+ g*time

Now the distance something falls is the average velocity, times time.

distance=(vfinal+vinitial)/2 * time

d=(1/2 (vinital+ g*time + vinitial)*time

= 1/2 (2vinitial*time + g*time^2)

= vinitial*time + 1/2 g*time^2

of course, 1/2 g = 4.9 m/s^2

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