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August 20, 2014

August 20, 2014

Posted by **jenny** on Friday, October 24, 2008 at 3:08pm.

Thank you!!

- college algebra -
**Reiny**, Friday, October 24, 2008 at 4:56pmI find it odd that your textbook stated the equation in this unsimplified form, since we could combine the two y terms to read

x^2 - 4x + y^2 - 3y + 8 = 0

From that form I recognize a circle.

let's complete the square:

x^2 - 4x + 4 + y^2 - 3y + 9/4 = -8+4+9/4

(x-2)^2 + (y-3/2)^2 = 1/4

so centre is (2,3/2) and radius is 1/2

we want to move this 1 unit down and 2 to the right, so

(x-2**-2**)^2 + (y-3/2**+1**)^2 = 1/4

(x-4)^2 + (y-1/2)^2 = 1/4

expand it if you will

new centre is (4,1/2), radius is still 1/2

- college algebra -
**jenny**, Friday, October 24, 2008 at 10:02pmIt was on a test. I think it was written like that to trick us. Normally I don't have a problem with math, but this teacher is pretty tricky! I really appreciate all of your help=;)

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