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October 22, 2014

October 22, 2014

Posted by **Joe** on Friday, October 24, 2008 at 2:43am.

- Calc -
**drwls**, Friday, October 24, 2008 at 5:27amLet u(v) = 3/v and v(x) = x^3 -4

The original function is u[v(x)]

du[v(x)]/dx = du/dv * dv/dx

= -3/v^2 * (3x^2)

= -x^2/(x^3 -4)^2

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