Thursday

November 27, 2014

November 27, 2014

Posted by **Joe** on Friday, October 24, 2008 at 2:43am.

- Calc -
**drwls**, Friday, October 24, 2008 at 5:27amLet u(v) = 3/v and v(x) = x^3 -4

The original function is u[v(x)]

du[v(x)]/dx = du/dv * dv/dx

= -3/v^2 * (3x^2)

= -x^2/(x^3 -4)^2

**Answer this Question**

**Related Questions**

MoRe HeLp PlEaSe!! (calc) - Also can I get some help with this LONG, TIRESOME ...

Calc I - How do I find the derivative for the sqrt(sin(e^(x^3)*cos(x)))??? I ...

calc - find the derivative of y = sqrt(9 - 16x) Use the chain rule. First find ...

calculus - Please help. Applying the chain rule, how do I find the derivative of...

Calculus - How do I use the chain rule to find the derivative of square root(1-x...

Calculus - find the derivative of f(x)=((x^2+3)^5+x)^2 using the chain rule. I ...

Calc - I'm creating a "calculu for dummies" project book. I've already done most...

Math - Calculus Question. - hey can someone explain to me the relationship ...

Calculus - y= [(x-3)/(x^2+1)]^2 find the derivative. I know i would start off ...

Chain Rule - Any help would be much appreciated with the steps involved in each ...