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posted by Joe on Friday, October 24, 2008 at 2:43am.
How would you find the derivative of (3/(x^3-4)) by using the chain rule?
Let u(v) = 3/v and v(x) = x^3 -4 The original function is u[v(x)] du[v(x)]/dx = du/dv * dv/dx = -3/v^2 * (3x^2) = -x^2/(x^3 -4)^2
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