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How would you find the derivative of (3/(x^3-4)) by using the chain rule?

  • Calc - ,

    Let u(v) = 3/v and v(x) = x^3 -4
    The original function is u[v(x)]

    du[v(x)]/dx = du/dv * dv/dx
    = -3/v^2 * (3x^2)
    = -x^2/(x^3 -4)^2

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