Posted by jean on Thursday, October 23, 2008 at 1:20pm.
A spelunker drops a stone from rest into a hole. The speed of sound is 343m/s in air, and the sound of the stone striking the bottom is heard 1.46s after the stone is dropped. How deep is the hole? What is it in meters

physics  bobpursley, Thursday, October 23, 2008 at 1:24pm
time=time down + time up
time=sqrt(2h/g)+ h/vsound
solve for time Use the quadratic equation.

physics  drwls, Thursday, October 23, 2008 at 1:28pm
Solve the equation
t1 + t2 =
(stone's time required to fall) + (time to hear the splash) = 1.46 s
(1/2) g t1^2 = H
t1 = sqrt (2H/g)
a H = t2 (a is the sound speed, 343 m/s)
t2 = H/a
You will have to set it up as a quadratic equation in H, the depth of the well.

physics  Anonymous, Tuesday, December 4, 2012 at 10:28pm
10.24

physics  Simanga Gamedze, Sunday, May 1, 2016 at 8:09am
a stone is dropped into a well . The sound of the splash is heard 30s after the stone is dropped . What is the depth of the well? Note that the speed of sound in air is 343m / s.
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