Wednesday
November 26, 2014

Homework Help: GK..please check...Chemistry Help Please

Posted by Sara on Wednesday, October 22, 2008 at 9:06pm.

Moles of S203^2- = (molarity)(volume):
=(0.032400 mol/L)(0.053 litres S203^2-)
= 0.03240 moles S203^2-

Moles if I2 based on Equation #2:
Moles I2 = (1/2)( 0.03240 moles S203^2-)
= .00086 moles I2

Moles of ClO^- based on Equation #1:
Moles ClO-(aq) = (2/3)(.00086 moles I2)
= .00057 moles ClO^3-

moles of ClO-(aq) = moles of NaOCl
.00057 moles ClO^3- = .00057 moles NaOCl

NaOCl mass = (molar mass * moles) = (74) (.00057) = 0.04235 g

Do we assume this gives us grams of NaOCl per 0.5 mL of bleach solution, since we didnít divide or multiply 0.0005 L with anything? And to make it NaOCl / 100 mLs of bleach do we multiply the by 100?

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

GK..please check...Chemistry Help Please - Sorry not leting me post entire thing...
GK or Dr.Bob222...Chemistry please help... - Please refer to the previous post ...
Chemistry: please double check... - Please double check one last time have to ...
chemistry - Initially, there are 33 moles of A and 0 moles of B. How many moles ...
Chemistry - I can not determine the answer for this problem...can someone please...
Chemistry - Calculate the average disappearance of A between t=0 min and t=10 ...
Chemistry - 3Cu+8HNO3--> 3Cu(NO3)2+ 2NO+4H2O How many moles of HNO3 are ...
Chemistry (stoichiometry - (This homework question has been removed due to a ...
Chemistry - How many mole of H2 will be produced if 0.500 grams of magnesium is ...
Chemistry - Given the balanced equation representing a reaction : 2Fe+ 3Cu^2...

Search
Members