# Finite Math

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Continental Motors manufactures taxis and airport limousines at its two plants. Plant A produces 75 taxis and 6 limousines daily, while plant B produces 50 taxis and 2 limousines daily. To fulfill its contractual obligations for November, the company must manufacture 3,124 taxis and 206 limousines. How many days should the company operate each plant if it wants to exactly meet its contracts?

Is the equation: 75t + 6L = 3,125
50t + 2L = 206

I have to find the equation before I can start with my augmented matrix. Can anyone help?

• Finite Math -

Days operating plant A = x
Days operating plant B = y

75 x + 50 y = 3124
6 x + 2 y = 206

• Finite Math -

Thank you so much!

• augmented matrix -

75 50 3124
6 2 206

1 2/3 41.65
1 1/3 34.33 subtract for new row 2

1 2/3 41.65
0 1/3 7.32 double row 2 and subtract for new row one
1 2/3 41.65
0 2/3 14.64

1 0 27.0
0 2/3 14.64 multiply row 2 by 3/2

1 0 27.0
0 1 22.0

• augmented matrix -

I don't particularly like to work with fractions so I went about it this way and came up with the same answer:

75 50 3125 6R1-75R2 into R2
6 2 206

75 50 3125
0 150 3300 R2 divided by 150 into R2

75 50 3125
0 1 1100 R1 - 50R2 into R1

75 0 2025
0 1 22 R1 - 50R2 into R1

75 0 2025
0 1 22 R1 divided by 75 into R1

1 0 27
0 1 22

Thanks again!