Thursday
March 23, 2017

Post a New Question

Posted by on Wednesday, October 22, 2008 at 6:34pm.

Jill and Matt run on a 400-meter-long oval track. They each run 10 laps daily and both run in the same lane. One day, they begin at the same point, but ran in opposite directions. Jill ran at a constant speed that was 2 meters per second faster than Matt's constant speed. Jill passed Matt for the first time in 40 seconds. Jill ran at a constant rate of how many meters per second?

Thanks in advance.

  • Math - , Wednesday, October 22, 2008 at 7:26pm

    Jill distance = x
    Matt distance = (400-x)
    Jill speed = j
    Matt speed = (j-2)

    distance = rate * time
    x = j (40)
    (400-x) = (j-2)(40)
    so
    (400 -40 j) = 40 j - 80
    I guess you can do it from there.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question